未解析的属性引用 'self'，属于StartResponse类

前端开发 2026-07-08

类型检查器似乎不太支持对 __self__ 的这种用法，并给出所示的错误。有人能解释这是为什么吗？我知道 WSGIref/types.py 并没有明确地定义 __self__，但我以为 __self__ 是Python（类实例化对象）的默认属性。

from typing import Iterator
from wsgiref import simple_server
from wsgiref.types import StartResponse

class Response:
    status: str
    start_response: StartResponse
    def __init__(self, start_response: StartResponse):
        self.start_response = start_response

class Controller:
    status: str
    start_response: StartResponse
    obj_response: Response
    def __init__(self, _: dict[str, str], start_response: StartResponse) -> None:
        self.obj_response = Response(start_response)
    def __iter__(self) -> Iterator[bytes]:
        self.obj_response.start_response('200 ok', [('Content-type', 'text/html; charset=utf-8')])
        self.status = self.obj_response.start_response.__self__.status
        # add the comment "#  type: ignore" at the end of the above line, as per suggestion by @jonrsharpe, to suppress the error
        print(self.status)
        yield b"hello world"

httpd = simple_server.make_server("", 8000, Controller)
httpd.serve_forever()

错误：

Unresolved attribute reference '__self__' for class 'StartResponse'

解决方案

就按这种方式：

class Response:
    def __init__(self, start_response):
        self.start_response = start_response
        self.status = ""

    def send(self, status, headers):
        self.status = status
        self.start_response(status, headers)


# and then
self.obj_response.send('200 OK', [('Content-Type', 'text/html; charset=utf-8')])
print(self.obj_response.status)

Python